Starting with the same initial conditions, an ideal gas expands from volume V 1 to V 2 in three different ways. The work done by the gas is W 1 if the process is purely isothermal. W 2 . if the process is purely adiabatic and W 3 if the process is purely isobaric. Then, choose the coned option
Text Solution
Verified by ExpertsThe correct answer is:
D
Area under curve is work
W 2 < W 1 < W 3
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